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先把 x x 当作幂函数(把指数上的 x 看作常数)求一次导,得 x x x 1 = x x, 再把 x x 当作指数函数(把底数上的 x 看作常数)求一次导,得 x x ln x, 最后把两者相加,得 (x x) = x x + x x ln x X Elite GPU性能 而在GPU方面,顶配的X Elite可以达到4.6 TFLOPS的算力,略低于M1 Pro。 很显然,X Elite的GPU不算弱,但终究还是高U低显的配置。 不过理论上倒是可以外接独立显卡,只是不知道显卡驱动到底什么时候能够准备好呢? 7月24日,推特(Twitter)平台颜色已正式更新为黑色,并启用“X”标志,告别原有的小蓝鸟形象。 今日早些时候,推特首席执行官琳达·亚卡里诺发文,宣…
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不超过实数x的最大整数称为x的整数部分,记作 [x]或INT (x)。 和整数部分紧密相关的是其小数部分,记为 {x},定义为 {x} =x- [x]。 由 [x]+1>x≥ [x]不难得知1> {x}≥0,反过来,若x= [x],自然有 {x}=0。 这些简单的事实有时很有用处,对于给定的,要求出 {x},先求出 [x]就.
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