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In cyclooctatetraene, the carbons are sp2 hybridized, which means a trigonal planar shape on each carbon It does not have a conjugated electron system. One consideration that may explain why cyclooctatetraene adopts a tub conformation is steric factors.
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The homotropylium cation is exactly what cyclooctatetraene rearranges into upon protonation Cyclohexane is not aromatic, even though it is circular The evidence for the aromatic nature of the homotropylium cation is ironclad
Nmr spectrometry is one of the best techniques to determine the presence and strength of aromaticity in a compound, due to aromatic ring currents.
The space group is aba Four structures can be postulated for the cyclooctatetraene molecule (see fig And the 'plane' form, which presumes a large resonance energy to overcome the strain. I don't understand what you mean, @mithoron
The [cycloheptatrienyl] anion is planar, which this post is about The regular cycloheptatriene molecule is not planar Would they not be more stable that way Why does this diradical state exist only in cyclobutadiene
Shouldn't other anti aromatic compounds, like cyclooctatetraene, also exist in a similar diradical state?
It appears to have a circular conjugated system, but it contains 8 electrons (4n+2=8 would require n=3/2)
